Rotary that has central position and draws arc to the left or right of center

General JUCE discussion
11

If anyone is looking for this still (like I did), I managed to get it working by simply starting the draw from 0 to the end angle which the default number from 0 is “2.51327” here is how the code looks like in my case to make it work like intended by OP:

//draw the value arcs
        if (slider.isEnabled() && slider.getValue() > 0)  {
            Path valueArc;
            valueArc.addCentredArc(centerX, centerY, knobRadius, knobRadius, 0.0f, 0, map(sliderPos, 0.5, 1.0, 0, 2.51327), true);
            std::cout << sliderPos << std::endl;
            g.setColour(valueFill);
            g.strokePath(valueArc, PathStrokeType(lineThickness));
        } else if (slider.isEnabled() && slider.getValue() < 0) {
            Path valueArc2;
            valueArc2.addCentredArc(centerX, centerY, knobRadius, knobRadius, 0.0f, 0, map(sliderPos, 0.5, 0.0, 0, -2.51327), true);
            std::cout << sliderPos << std::endl;
            g.setColour(valueFill);
            g.strokePath(valueArc2, PathStrokeType(lineThickness));
        }

Pay attention to this:

valueArc.addCentredArc(centerX, centerY, knobRadius, knobRadius, 0.0f, 0, map(sliderPos, 0.5, 1.0, 0, 2.51327), true);

this draws from centre to the right, whereas this:

valueArc2.addCentredArc(centerX, centerY, knobRadius, knobRadius, 0.0f, 0, map(sliderPos, 0.5, 0.0, 0, -2.51327), true);

draws from centre to left. It only has inverted end angle, just put a minus before it.

Hope this helps people!