Access to JuceUIViewController

[jacobsologub]

What’s the best way to get at the JuceUIViewController in UIViewComponentPeer?

[jacobsologub]

never-mind got it.

[code]UIResponder* responder = ((UIView*) Desktop::getInstance().getComponent (0)->getWindowHandle()).nextResponder;

if ([responder isKindOfClass: [UIViewController class]])
{
UIViewController* controller = (UIViewController*) responder;
//xxx
}
[/code]

UIResponder Class Reference

The UIResponder class does not store or set the next responder automatically, instead returning nil by default. Subclasses must override this method to set the next responder. UIView implements this method by returning the UIViewController object that manages it (if it has one) or its superview (if it doesn’t); UIViewController implements the method by returning its view’s superview; UIWindow returns the application object, and UIApplication returns nil.

Now the only suspect here is:

getComponent (0)

Is this always going to give me that one JuceUIView on iOS? Is there a better way to guaranty this?

Or should I use:

UIResponder* responder = ((UIView*) [[UIApplication sharedApplication].keyWindow.subviews objectAtIndex: 0]).nextResponder;

Since I’m already dealing with iOS stuff here, why not fall back on [UIApplication sharedApplication].keyWindow, there’s only one window on iOS.

Would this be more solid than:

Desktop::getInstance().getComponent (0)->getWindowHandle()

?

That zero index just scares me for some reason no matter what approach…

-Thanks

[jules]

I’d probably opt for something like Component::getCurrentlyFocusedComponent() rather than using the Desktop class.