this used to work and was introduced quite recently. reproduction:
auto x = std::string() + String();
Cheers,
Ben
this used to work and was introduced quite recently. reproduction:
auto x = std::string() + String();
Cheers,
Ben
@jules added an explicit overload to operator+
in https://github.com/WeAreROLI/JUCE/commit/4793cd3fb8efd0ea4680ef4a86e4a37c2b1c9c96.
@pixelpacker what do you expect x
to be in your example? A juce::String
or a std::string
?
To be explicit (and avoid the ambiguity), you can re-write your example as:
auto x = String{std::string{}} + String{};
or
auto x = std::string{} + String{}.toStdString();