Hello
Perhaps a stupid question, but why JUCE uses specific typedefs like juce::uint8, juce::uint32 ???
With C++ 11, there are already types like uint8_t or uint32_t.
Hello
Perhaps a stupid question, but why JUCE uses specific typedefs like juce::uint8, juce::uint32 ???
With C++ 11, there are already types like uint8_t or uint32_t.
JUCE predates C++11, and thus, these datatypes were created back then. I think the JUCE team should do a search-replace and get rid of those custom types.
Discussed previously here:
tl;dr this would be a breaking change with few benefits to justify the cost.
If you look at the code, for instance for int8:
namespace juce
{
/** A platform-independent 8-bit signed integer type. */
using int8 = signed char;
}
The keyword “using” exists since C+11 … I guess that before C+11 it was a #define ?